Alcohols, Phenols and Ethers

Which of the following compound gives pink colour on reaction with phthalic anhydride in conc. H$_2$SO$_4$ followed by treatment with NaOH ?

What is the final product (major) 'A' in the given reaction ?

Identify products A and B.

1-Methylcyclopentene is treated with dil. KMnO$_4$ at 273 K to give A, which with CrO$_3$ gives B.

In the reaction scheme shown below, Q, R, and S are the major products.

The correct structure of

An organic compound ($\ce{C8H10O2}$) rotates plane-polarized light. It produces pink color with neutral $\ce{FeCl3}$ solution. What is the total number of all the possible isomers for this compound?

Choose the correct option(s) for the following set of reactions

Schemes 1 and 2 describe the conversion of P to Q and R to S, respectively. Scheme 3 describes the synthesis of T from Q and S. The total number of Br atoms in a molecule of T is ______

Total number of hydroxyl groups present in a molecule of the major product P is ______

Which of the following options has correct combination considering List-I and List-II?

Which of the following options has correct combination considering List-I and List-II?

The compound R is

The desired product X can be prepared by reacting the major product of the reactions in LIST-I with one or more appropriate reagents in LIST-II.

(given, order of migratory aptitude: aryl > alkyl > hydrogen)

The correct option is

LIST-I contains reactions and LIST-II contains major products.

Match each reaction in LIST-I with one or more products in LIST-II and choose the correct option.

The major product of the following reaction is

The product S is

The major product of the following reaction is :

The increasing order of the boiling points for the following compounds is :

$\ce{C2H5OH}$ (I), $\ce{C2H5Cl}$ (II), $\ce{C2H5CH3}$ (III), $\ce{C2H5OCH3}$ (IV)

In the following reaction sequence :
$$\underset{(\ce{C3H6Cl2})}{\text{I}}\ce{->[KOH(aq)]}\text{II}\xrightarrow[\text{(ii) }\ce{H2O/H+}]{\text{(i) }\ce{CH3MgBr}}\text{III}\xrightarrow{\text{Anhy. }\ce{ZnCl2}\text{ + Con. HCl}}\text{gives turbidity immediately}$$
The compound I is :

The correct statement(s) about the following reaction sequence is(are)

$$\text{Cumene }(\ce{C9H12})\xrightarrow[\text{ii) }\ce{H3O+}]{\text{i) }\ce{O2}}\mathbf P\xrightarrow{\ce{CHCl3/NaOH}}\mathbf Q\text{ (major)}+\mathbf R\text{ (minor)}$$
$$\mathbf Q\xrightarrow[\ce{PhCH2Br}]{\ce{NaOH}}\mathbf S$$

The gas evolved on heating $\ce{CH3MgBr}$ in methanol is :