JEE Main 2017 · 9 Apr · Shift 1 · Chemistry Q57

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ChemistrySingle correct+4 / -1Question 57 of 90

The increasing order of the boiling points for the following compounds is :

$\ce{C2H5OH}$ (I), $\ce{C2H5Cl}$ (II), $\ce{C2H5CH3}$ (III), $\ce{C2H5OCH3}$ (IV)

(III) < (IV) < (II) < (I)

(IV) < (III) < (I) < (II)

(II) < (III) < (IV) < (I)

(III) < (II) < (I) < (IV)

Answer and worked solution

Official answer: A

Propane (III, non-polar) boils lowest, then the ether (IV), then chloroethane (II, more polar and heavier), and ethanol (I, hydrogen-bonded) highest: III < IV < II < I.

Topics:Alcohols Hydrogen bonding

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JEE Main 2017 · 9 Apr · Shift 1, Chemistry question 57