JEE Main 2022 · 28 Jul · Shift 1 · Physics Q44

← JEE Main 2022 · 28 Jul · Shift 1

PhysicsSingle correct+4 / -1Question 44 of 90

The equation of current in a purely inductive circuit is $5\sin(49\pi t-30^\circ)$ . If the inductance is 30 mH then the equation for the voltage across the inductor, will be :

$\left\{\text{Let }\pi=\dfrac{22}7\right\}$

1.47\sin(49\pi t-30^\circ)

1.47\sin(49\pi t+60^\circ)

23.1\sin(49\pi t-30^\circ)

23.1\sin(49\pi t+60^\circ)

Answer and worked solution

Official answer: D

Reactance $X_L=49\pi\times0.03=4.62$ Ω, so $V_0=5\times4.62=23.1$ V.

Phase. The voltage leads the current by 90°: $23.1\sin(49\pi t+60^\circ)$ .

(D)

Topics:Reactance and impedance

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JEE Main 2022 · 28 Jul · Shift 1, Physics question 44