JEE Main 2022 · 28 Jul · Shift 1 · Physics Q45

PhysicsSingle correct+4 / -1Question 45 of 90

As shown in the figure, after passing through the medium 1. The speed of light $v_2$ in medium 2 will be :

(Given $c=3\times10^8$ ms $^{-1}$ )

1.0\times10^8

^{-1}

0.5\times10^8

^{-1}

1.5\times10^8

^{-1}

3.0\times10^8

^{-1}

Answer and worked solution

Official answer: A

$v=\frac c{\sqrt{\mu_r\varepsilon_r}}$ $=\frac{3\times10^8}3=1.0\times10^8$ m s $^{-1}$ .

(A)

Topics:Properties of EM waves

JEE Main 2022 · 28 Jul · Shift 1, Physics question 45