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← JEE Main 2022 · 28 Jul · Shift 1
PhysicsSingle correct+4 / -1Question 43 of 90

JEE Main 2022 · 28 Jul · Shift 1, Physics question 43

As shown in the figure, a metallic rod of linear density 0.45 kg m−1^{-1} is lying horizontally on a smooth inclined plane which makes an angle of 45° with the horizontal. The minimum current flowing in the rod required to keep it stationary, when 0.15 T magnetic field is acting on it in the vertical upward direction, will be :

{Use g = 10 m/s2^2}

A horizontal rod lying across a smooth 45° incline carrying current I, with a uniform field B pointing vertically upward.
Choose one option
Answer and worked solution

Official answer: A

Along the incline. The horizontal force IlBIlB balances gravity: IlBcos⁡45∘=mgsin⁡45∘IlB\cos45^\circ=mg\sin45^\circ.

I=0.45×100.15=30I=\frac{0.45\times10}{0.15}=30 A. (A)