JEE Main 2026 · 6 Apr · Shift 2 · Chemistry Q53

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ChemistrySingle correct+4 / -1Question 53 of 75

Given below are two statements :

Statement I : The number of compounds among $\ce{SO2}$ , $\ce{SO3}$ , $\ce{SF4}$ , $\ce{SF6}$ and $\ce{H2S}$ in which sulphur does not obey the Octet rule is 3.

Statement II : Among $[\ce{H2O},\ \ce{ClF3},\ \ce{SF4}]$ , $[\ce{NH3},\ \ce{BrF5},\ \ce{SF4}]$ , $[\ce{BrF5},\ \ce{ClF3},\ \ce{XeF4}]$ and $[\ce{XeF4},\ \ce{ClF3},\ \ce{H2O}]$ , the number of sets in which all the molecules have one lone pair of electrons on the central atom is 1.

In the light of the above statements, choose the correct answer from the options given below :

Both Statement I and Statement II are true

Both Statement I and Statement II are false

Statement I is true but Statement II is false

Statement I is false but Statement II is true

Answer and worked solution

Official answer: D

Statement I. In the usual Lewis structures, S has more than 8 electrons in $\ce{SO2}$ , $\ce{SO3}$ , $\ce{SF4}$ and $\ce{SF6}$ (expanded octets); only $\ce{H2S}$ obeys the octet. That is 4, not 3. False.

Statement II. Lone pairs on the central atom: $\ce{H2O}$ 2, $\ce{ClF3}$ 2, $\ce{XeF4}$ 2; $\ce{NH3}$ , $\ce{BrF5}$ and $\ce{SF4}$ 1 each. Only $[\ce{NH3},\ce{BrF5},\ce{SF4}]$ qualifies: 1 set. True.

(D)

Topics:VSEPR theory Covalent bonding and Lewis structures

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JEE Main 2026 · 6 Apr · Shift 2, Chemistry question 53