JEE Main 2026 · 6 Apr · Shift 2 · Chemistry Q52

ChemistrySingle correct+4 / -1Question 52 of 75

The Bohr radius of a hydrogen like species is 70.53 pm. The species and the stationary state (n) are respectively

(Given : Hydrogen atom Bohr radius is 52.9 pm)

\ce{Li^2+}

, 3

\ce{He+}

, 3

\ce{He+}

, 2

\ce{Li^2+}

, 2

Answer and worked solution

Official answer: D

Bohr radius. $r=52.9\dfrac{n^2}Z$ , so $\dfrac{n^2}Z=\dfrac{70.53}{52.9}=\dfrac43$ .

So $n=2$ , $Z=3$ : $\ce{Li^2+}$ , $n=2$ .

(D)

Topics:Bohr model

JEE Main 2026 · 6 Apr · Shift 2, Chemistry question 52