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JEE Main 2026 · 6 Apr · Shift 2, Chemistry question 54

Match List - I with List - II.

Given V1V_1 and V2V_2 are initial and final volumes respectively.

Choose the correct answer from the options given below :

List - I (Isothermal process)

  • A
    Reversible expansion
  • B
    Free expansion
  • C
    Irreversible Compression
  • D
    Cyclic reversible

List - II (Expression)

  • I
    q=0q=0
  • II
    q=nRTln⁡V2V1q=nRT\ln\dfrac{V_2}{V_1}
  • III
    w=−pext(V1−V2)w=-p_{ext}(V_1-V_2)
  • IV
    qrevT=0\dfrac{q_{rev}}T=0
Choose one option
Answer and worked solution

Official answer: C

Each isothermal process.

  • A: Reversible expansion: q=nRTln⁡V2V1q=nRT\ln\dfrac{V_2}{V_1} (II).
  • B: Free expansion: w=0w=0 and ΔU=0\Delta U=0, so q=0q=0 (I).
  • C: Irreversible compression against pextp_{ext} (III). With the usual convention w=−pext(V2−V1)w=-p_{ext}(V_2-V_1); III is printed with V1−V2V_1-V_2.
  • D: Cyclic reversible: ∮qrevT=0\oint\dfrac{q_{rev}}T=0 (IV).

Match: A-II, B-I, C-III, D-IV.

(C)