JEE Main 2022 · 30 Jul · Shift 2 · Chemistry Q55

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ChemistryInteger+4 / -1Question 55 of 90

For the given cell Zn(s) | Zn $^{2+}$ (C $_1$ M) || Zn $^{2+}$ (C $_2$ M) | Zn(s) the change in Gibbs energy (ΔG) will be zero when $\dfrac{C_1}{C_2}$ is equal to _______.

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Answer and worked solution

Official answer: 1

Concentration cell. $E=\frac{0.059}2\log\frac{C_2}{C_1}$ is zero, and so is ΔG, when $C_1=C_2$ .

Answer: 1

Topics:Nernst equation Gibbs energy and EMF

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JEE Main 2022 · 30 Jul · Shift 2, Chemistry question 55