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← JEE Main 2022 · 30 Jul · Shift 2
ChemistryInteger+4 / -1Question 56 of 90

JEE Main 2022 · 30 Jul · Shift 2, Chemistry question 56

X → Y + Z

X decomposes at 700 K to give Y and Z. The results of two measurements are :

Initial concentration of X / (mol/L) 6.0 12.0
Half life / s 1.0 2.0

The rate constant for the reaction is _______ (in appropriate unit)

Answer and worked solution

Official answer: 3

Order. Half-life doubles when [X]0[X]_0 doubles, so the reaction is zero order and t1/2=[X]02kt_{1/2}=\frac{[X]_0}{2k}.

Rate constant k=6.02×1.0=3k=\frac{6.0}{2\times1.0}=3 mol L⁻¹ s⁻¹.

Answer: 3