JEE Main 2022 · 30 Jul · Shift 2 · Chemistry Q54

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ChemistryInteger+4 / -1Question 54 of 90

50 mL of 0.1 M CH $_3$ COOH is titrated against 0.1 M NaOH solution. When 10 mL of NaOH is added, the pH of the solution becomes _______ $\times10^{-1}$ . (nearest integer)

Given: pKa (CH $_3$ COOH) = 4.8, log 2 = 0.3

Your answer

Answer and worked solution

Official answer: 42

Buffer. 1 mmol of acetate and 4 mmol of acid remain: pH $=4.8+\log\frac14=4.8-0.6=4.2=42\times10^{-1}$ .

Answer: 42

Topics:Buffer solutions Indicators and titrations

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JEE Main 2022 · 30 Jul · Shift 2, Chemistry question 54