JEE Main 2022 · 29 Jul · Shift 2 · Physics Q37

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PhysicsSingle correct+4 / -1Question 37 of 90

A juggler throws balls vertically upwards with same initial velocity in air. When the first ball reaches its highest position, he throws the next ball. Assuming the juggler throws n balls per second, the maximum height the balls can reach is

g/2n

g/n

2gn

g/2n

^2

Answer and worked solution

Official answer: D

Timing. Each ball reaches the top in $\frac1n$ s, so $u=\frac gn$ and $H=\frac{u^2}{2g}=\frac g{2n^2}$ .

(D)

Topics:Motion in a straight line

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JEE Main 2022 · 29 Jul · Shift 2, Physics question 37