JEE Main 2022 · 29 Jul · Shift 2 · Physics Q36

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PhysicsSingle correct+4 / -1Question 36 of 90

A wire X of length 50 cm carrying a current of 2 A is placed parallel to a long wire Y of length 5 m. The wire Y carries a current of 3 A. The distance between two wires is 5 cm and currents flow in the same direction. The force acting on the wire Y is

A short wire X carrying 2 A upward placed 5 cm to the left of a long wire Y carrying 3 A upward.

1.2\times10^{-5}

N directed towards wire X.

1.2\times10^{-4}

N directed away from wire X.

1.2\times10^{-4}

N directed towards wire X.

2.4\times10^{-5}

N directed towards wire X.

Answer and worked solution

Official answer: A

Newton's third law. The force on Y equals the force on the 50 cm wire X: $\dfrac{\mu_0I_1I_2L}{2\pi d}=\dfrac{2\times10^{-7}\times6\times0.5}{0.05}=1.2\times10^{-5}$ N. Parallel currents attract, so it points towards X.

(A)

Topics:Force on a current-carrying conductor

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JEE Main 2022 · 29 Jul · Shift 2, Physics question 36