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← JEE Main 2022 · 28 Jul · Shift 1
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JEE Main 2022 · 28 Jul · Shift 1, Physics question 46

In normal adjustment, for a refracting telescope, the distance between objective and eye piece is 30 cm. The focal length of the objective, when the angular magnification of the telescope is 2, will be :

Choose one option
Answer and worked solution

Official answer: A

Normal adjustment. fo+fe=30f_o+f_e=30 and fofe=2\frac{f_o}{f_e}=2, so fo=20f_o=20 cm.

(A)