JEE Main 2022 · 28 Jul · Shift 1 · Physics Q47

PhysicsSingle correct+4 / -1Question 47 of 90

The equation $\lambda=\dfrac{1.227}x$ nm can be used to find the de-Brogli wavelength of an electron. In this equation $x$ stands for :

Where m = mass of electron
P = momentum of electron
K = Kinetic energy of electron
V = Accelerating potential in volts for electron

\sqrt{mK}

\sqrt P

\sqrt K

\sqrt V

Answer and worked solution

Official answer: D

$\lambda=\frac h{\sqrt{2meV}}=\frac{1.227}{\sqrt V}$ nm.

(D)

Topics:de Broglie waves

JEE Main 2022 · 28 Jul · Shift 1, Physics question 47