JEE Main 2022 · 25 Jul · Shift 2 · Mathematics Q8

MathematicsSingle correct+4 / -1Question 8 of 90

If A and B are two events such that $P(A)=\dfrac13$ , $P(B)=\dfrac15$ and $P(A\cup B)=\dfrac12$ , then $P(A|B')+P(B|A')$ is equal to

\dfrac34

\dfrac58

\dfrac54

\dfrac78

Answer and worked solution

Official answer: B

Intersection $P(A\cap B)=\frac13+\frac15-\frac12=\frac1{30}$ .

Sum. $\dfrac{3/10}{4/5}+\dfrac{1/6}{2/3}=\frac38+\frac14=\frac58$ .

(B)

Topics:Conditional probability

JEE Main 2022 · 25 Jul · Shift 2, Mathematics question 8