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← JEE Main 2022 · 25 Jul · Shift 2
MathematicsSingle correct+4 / -1Question 9 of 90

JEE Main 2022 · 25 Jul · Shift 2, Mathematics question 9

Let [t][t] denote the greatest integer less than or equal to tt. Then the value of the integral ∫−3101([sin⁡(πx)]+e[cos⁡(2πx)])dx\displaystyle\int_{-3}^{101}\left([\sin(\pi x)]+e^{[\cos(2\pi x)]}\right)dx is equal to

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Answer and worked solution

Official answer: B

Period 2 for [sin⁡πx][\sin\pi x] (integral −1-1 per period) and period 1 for e[cos⁡2πx]e^{[\cos2\pi x]} (value 1 on half the period, e−1e^{-1} on the other half).

Over 104 units. −52+104⋅12(1+e−1)=52e-52+104\cdot\frac12(1+e^{-1})=\frac{52}e.

(B)