JEE Main 2022 · 25 Jul · Shift 2, Mathematics question 7

$\displaystyle\lim_{n\to\infty}\frac1{2^n}\left(\frac1{\sqrt{1-\frac1{2^n}}}+\frac1{\sqrt{1-\frac2{2^n}}}+\frac1{\sqrt{1-\frac3{2^n}}}+\dots+\frac1{\sqrt{1-\frac{2^n-1}{2^n}}}\right)$ is equal to