Skip to content
dronacharya.ai
← JEE Main 2022 · 30 Jun · Shift 1
PhysicsInteger+4 / -1Question 59 of 90

JEE Main 2022 · 30 Jun · Shift 1, Physics question 59

A hydrogen atom in its first excited state absorbs a photon of energy x×10−2x\times10^{-2} eV and excited to a higher energy state where the potential energy of electron is −1.08-1.08 eV. The value of xx is ______.

Answer and worked solution

Official answer: 286

Level. U=−27.2n2=−1.08U=-\frac{27.2}{n^2}=-1.08 gives n=5n=5.

Energy from n=2n=2: 13.6(14−125)=2.85613.6\left(\frac14-\frac1{25}\right)=2.856 eV ≈286×10−2\approx286\times10^{-2} eV.

Answer: 286