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← JEE Main 2022 · 30 Jun · Shift 1
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JEE Main 2022 · 30 Jun · Shift 1, Physics question 58

The refractive index of an equilateral prism is 2\sqrt2. The angle of emergence under minimum deviation position of prism, in degree, is ______.

Answer and worked solution

Official answer: 45

Minimum deviation. sin⁡60°+δ2=2sin⁡30°\sin\frac{60°+\delta}2=\sqrt2\sin30°, so 60°+δ2=45°\frac{60°+\delta}2=45° and e=i=45°e=i=45°.

Answer: 45