JEE Main 2022 · 29 Jun · Shift 2 · Physics Q47

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PhysicsSingle correct+4 / -1Question 47 of 90

A block of mass M placed inside a box descends vertically with acceleration 'a'. The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of 'a' will be

\dfrac g4

\dfrac g2

\dfrac{3g}4

g

Answer and worked solution

Official answer: C

Normal force. $M(g-a)=\frac{Mg}4$ , so $a=\frac{3g}4$ .

(C)

Topics:Newton's laws

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JEE Main 2022 · 29 Jun · Shift 2, Physics question 47