JEE Main 2022 · 29 Jun · Shift 2 · Physics Q46

PhysicsSingle correct+4 / -1Question 46 of 90

In the given figure, the block of mass $m$ is dropped from the point 'A'. The expression for kinetic energy of block when it reaches point 'B' is

\dfrac12mgy_0^2

\dfrac12mgy^2

mg\left(y-y_0\right)

mgy_0

Answer and worked solution

Official answer: D

Fall from A to B is $y_0$ : kinetic energy $mgy_0$ .

(D)

Topics:Conservation of mechanical energy

JEE Main 2022 · 29 Jun · Shift 2, Physics question 46