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← JEE Main 2022 · 29 Jun · Shift 2
PhysicsSingle correct+4 / -1Question 48 of 90

JEE Main 2022 · 29 Jun · Shift 2, Physics question 48

If the electric potential at any point (x,y,z)(x,y,z) m in space is given by V=3x2V=3x^2 volt. The electric field at the point (1,0,3)(1,0,3) m will be :

Choose one option
Answer and worked solution

Official answer: D

Field. Ex=−dVdx=−6x=−6E_x=-\dfrac{dV}{dx}=-6x=-6 V m−1^{-1} at x=1x=1: magnitude 6, along −x-x.

(D)