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← JEE Main 2022 · 29 Jun · Shift 1
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JEE Main 2022 · 29 Jun · Shift 1, Physics question 56

300 cal. of heat is given to a heat engine and it rejects 225 cal. of heat. If source temperature is 227°C, then the temperature of sink will be ______ °C.

Answer and worked solution

Official answer: 102

Carnot ratio. T2T1=225300\frac{T_2}{T_1}=\frac{225}{300}, so T2=0.75×500=375T_2=0.75\times500=375 K =102=102 °C.

Answer: 102