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← JEE Main 2022 · 29 Jun · Shift 1
PhysicsInteger+4 / -1Question 55 of 90

JEE Main 2022 · 29 Jun · Shift 1, Physics question 55

The variation of applied potential and current flowing through a given wire is shown in figure. The length of wire is 31.4 cm. The diameter of wire is measured as 2.4 cm. The resistivity of the given wire is measured as x×10−3x\times10^{-3} Ω\Omega cm. The value of xx is ______.

[Take π=3.14\pi=3.14]

Potential (volt) against I (A): a straight line through the origin at 45° to the I axis.
Answer and worked solution

Official answer: 144

Resistance. The 45° line gives R=1R=1 Ω.

Resistivity. ρ=RAL=3.14×1.2231.4=0.144\rho=\dfrac{RA}L=\dfrac{3.14\times1.2^2}{31.4}=0.144 Ω cm =144×10−3=144\times10^{-3} Ω cm.

Answer: 144