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JEE Main 2022 · 28 Jun · Shift 2, Physics question 51

A student in the laboratory measures thickness of a wire using screw gauge. The readings are 1.22 mm, 1.23 mm, 1.19 mm and 1.20 mm. The percentage error is x121\dfrac x{121}%. The value of xx is ______.

Answer and worked solution

Official answer: 150

Mean 1.211.21 mm; absolute deviations 0.01,0.02,0.02,0.010.01,0.02,0.02,0.01, mean 0.0150.015 mm.

Percentage error. 0.0151.21×100=150121%\dfrac{0.015}{1.21}\times100=\dfrac{150}{121}\%.

Answer: 150