JEE Main 2022 · 28 Jun · Shift 2 · Physics Q52

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A zener of breakdown voltage $V_Z=8$ V and maximum zener current, $I_{ZM}=10$ mA is subjected to an input voltage $V_i=10$ V with series resistance $R=100\ \Omega$ . In the given circuit $R_L$ represents the variable load resistance. The ratio of maximum and minimum value of $R_L$ is ______.

Zener regulator: a 10 V source in series with R = 100 Ω; a reverse-biased zener (V_z = 8 V, I_ZM = 10 mA) in parallel with a variable load R_L.

Your answer

Answer and worked solution

Official answer: 2

Current through R. $\frac{10-8}{100}=20$ mA.

Load current ranges from $20-10=10$ mA to 20 mA: $R_L$ from $\frac8{0.02}=400$ Ω to $\frac8{0.01}=800$ Ω.

Ratio 2.

Answer: 2

Topics:Special diodes (LED, Zener, photodiode, solar cell)

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JEE Main 2022 · 28 Jun · Shift 2, Physics question 52