JEE Main 2022 · 28 Jun · Shift 2 · Physics Q50

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Amplitude modulated wave is represented by

$V_{AM}=10\left[1+0.4\cos\left(2\pi\times10^4t\right)\right]\cos\left(2\pi\times10^7t\right)$ . The total bandwidth of the amplitude modulated wave is :

10 kHz

20 MHz

20 kHz

10 MHz

Answer and worked solution

Official answer: C

Sidebands at $f_c\pm f_m$ with $f_m=10^4$ Hz: bandwidth $2f_m=20$ kHz.

(C)

Topics:Modulation

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JEE Main 2022 · 28 Jun · Shift 2, Physics question 50