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← JEE Main 2022 · 27 Jun · Shift 1
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JEE Main 2022 · 27 Jun · Shift 1, Physics question 51

In a carnot engine, the temperature of reservoir is 527°C and that of sink is 200 K. If the workdone by the engine when it transfers heat from reservior to sink is 12000 kJ, the quantity of heat absorbed by the engine from reservoir is ______ ×106\times10^6 J.

Answer and worked solution

Official answer: 16

Efficiency. 1−200800=0.751-\dfrac{200}{800}=0.75.

Heat absorbed. 12000 kJ0.75=16000\dfrac{12000\text{ kJ}}{0.75}=16000 kJ =16×106=16\times10^6 J.

Answer: 16