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← JEE Main 2022 · 27 Jun · Shift 1
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JEE Main 2022 · 27 Jun · Shift 1, Physics question 52

A 220 V, 50 Hz AC source is connected to a 25 V, 5 W lamp and an additional resistance R in series (as shown in figure) to run the lamp at its peak brightness, then the value of R (in ohm) will be ______.

A 25 V, 5 W lamp in series with a resistor R across a 220 V, 50 Hz AC source.
Answer and worked solution

Official answer: 975

Lamp. Current 525=0.2\frac5{25}=0.2 A and resistance 125 Ω125\ \Omega.

Series resistance. Total 2200.2=1100 Ω\frac{220}{0.2}=1100\ \Omega, so R=975 ΩR=975\ \Omega.

Answer: 975