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JEE Main 2022 · 27 Jun · Shift 1, Physics question 50

A mixture of hydrogen and oxygen has volume 2000 cm3^3, temperature 300 K, pressure 100 kPa and mass 0.76 g. The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be :

[Take gas constant R=8.3R=8.3 JK−1^{-1}mol−1^{-1}]

Choose one option
Answer and worked solution

Official answer: B

Total moles. n=PVRT=105×2×10−38.3×300≈0.0803n=\dfrac{PV}{RT}=\dfrac{10^5\times2\times10^{-3}}{8.3\times300}\approx0.0803.

Mass. 2nH+32nO=0.762n_H+32n_O=0.76 with nH+nO=0.0803n_H+n_O=0.0803: nO≈0.020n_O\approx0.020, nH≈0.060n_H\approx0.060.

Ratio 3:13:1.

(B)

Topics:Ideal gas equation
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