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← JEE Main 2022 · 25 Jun · Shift 2
PhysicsSingle correct+4 / -1Question 31 of 90

JEE Main 2022 · 25 Jun · Shift 2, Physics question 31

Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Two identical balls AA and BB thrown with same velocity 'uu' at two different angles with horizontal attained the same range RR. If AA and BB reached the maximum height h1h_1 and h2h_2 respectively, then R=4h1h2R=4\sqrt{h_1h_2}

Reason R: Product of said heights.
h1h2=(u2sin⁡2θ2g)⋅(u2cos⁡2θ2g)h_1h_2=\left(\frac{u^2\sin^2\theta}{2g}\right)\cdot\left(\frac{u^2\cos^2\theta}{2g}\right)
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Answer and worked solution

Official answer: A

Same range at speed uu means complementary angles θ\theta and 90°−θ90°-\theta, so h1=u2sin⁡2θ2gh_1=\dfrac{u^2\sin^2\theta}{2g} and h2=u2cos⁡2θ2gh_2=\dfrac{u^2\cos^2\theta}{2g} (R is true).

Then h1h2=u2sin⁡θcos⁡θ2g=R4\sqrt{h_1h_2}=\dfrac{u^2\sin\theta\cos\theta}{2g}=\dfrac R4, so R=4h1h2R=4\sqrt{h_1h_2} (A is true, and follows from R).

(A)