JEE Main 2022 · 25 Jun · Shift 2 · Physics Q32

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PhysicsSingle correct+4 / -1Question 32 of 90

Two buses $P$ and $Q$ start from a point at the same time and move in a straight line and their positions are represented by $X_P(t)=\alpha t+\beta t^2$ and $X_Q(t)=ft-t^2$ . At what time, both the buses have same velocity ?

\dfrac{\alpha-f}{1+\beta}

\dfrac{\alpha+f}{2(\beta-1)}

\dfrac{\alpha+f}{2(1+\beta)}

\dfrac{f-\alpha}{2(1+\beta)}

Answer and worked solution

Official answer: D

Velocities. $v_P=\alpha+2\beta t$ , $v_Q=f-2t$ .

Equal. $\alpha+2\beta t=f-2t$ gives $t=\dfrac{f-\alpha}{2(1+\beta)}$ .

(D)

Topics:Motion in a straight line

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JEE Main 2022 · 25 Jun · Shift 2, Physics question 32