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← JEE Main 2022 · 25 Jun · Shift 2
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JEE Main 2022 · 25 Jun · Shift 2, Mathematics question 30

Let l1l_1 be the line in xyxy-plane with xx and yy intercepts 18\dfrac18 and 142\dfrac1{4\sqrt2} respectively, and l2l_2 be the line in zxzx-plane with xx and zz intercepts −18-\dfrac18 and −163-\dfrac1{6\sqrt3} respectively. If dd is the shortest distance between the line l1l_1 and l2l_2, then d−2d^{-2} is equal to ______.

Answer and worked solution

Official answer: 51

Lines. l1l_1 through (18,0,0)\left(\frac18,0,0\right) with direction (1,−2,0)(1,-\sqrt2,0); l2l_2 through (−18,0,0)\left(-\frac18,0,0\right) with direction (1,0,−433)\left(1,0,-\frac4{3\sqrt3}\right).

Common normal. n⃗∝(1,12,334)\vec n\propto\left(1,\frac1{\sqrt2},\frac{3\sqrt3}4\right), with ∣n⃗∣2=1+12+2716=5116|\vec n|^2=1+\frac12+\frac{27}{16}=\frac{51}{16}.

Distance. d=∣(−14,0,0)⋅n⃗∣∣n⃗∣=1/451/4=151d=\dfrac{\left|\left(-\frac14,0,0\right)\cdot\vec n\right|}{|\vec n|}=\dfrac{1/4}{\sqrt{51}/4}=\dfrac1{\sqrt{51}}, so d−2=51d^{-2}=51.

Answer: 51