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← JEE Main 2017 · 9 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 65 of 90

JEE Main 2017 · 9 Apr · Shift 1, Mathematics question 65

If x=ax=a, y=by=b, z=cz=c is a solution of the system of linear equations
x+8y+7z=0x+8y+7z=0
9x+2y+3z=09x+2y+3z=0
x+y+z=0x+y+z=0
such that the point (a, b, c) lies on the plane x+2y+z=6x+2y+z=6, then 2a+b+c2a+b+c equals :

Choose one option
Answer and worked solution

Official answer: C

Subtracting the third equation from the first, 7y+6z=07y+6z=0. Then x=−y−zx=-y-z, and the second equation holds. The solutions are (a,b,c)=k(1,6,−7)(a,b,c)=k(1,6,-7). On the plane, k(1+12−7)=6k(1+12-7)=6, so k=1k=1 and 2a+b+c=2+6−7=12a+b+c=2+6-7=1.