JEE Main 2017 · 9 Apr · Shift 1 · Mathematics Q66

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MathematicsSingle correct+4 / -1Question 66 of 90

The number of ways in which 5 boys and 3 girls can be seated on a round table if a particular boy $B_1$ and a particular girl $G_1$ never sit adjacent to each other, is :

5\times6!

6\times6!

5\times7!

Answer and worked solution

Official answer: A

8 people round a table: $7!$ arrangements. With $B_1$ and $G_1$ together: $6!\times2$ . So the count is $7!-2\cdot6!=5\times6!$ .

Topics:Permutations

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JEE Main 2017 · 9 Apr · Shift 1, Mathematics question 66