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← JEE Main 2017 · 9 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 64 of 90

JEE Main 2017 · 9 Apr · Shift 1, Mathematics question 64

For two 3 × 3 matrices A and B, let A+B=2B′A+B=2B' and 3A+2B=I33A+2B=I_3, where B′ is the transpose of B and I3I_3 is 3 × 3 identity matrix. Then :

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Answer and worked solution

Official answer: B

From A=2B′−BA=2B'-B, 3A+2B=6B′−B=I3A+2B=6B'-B=I. Transposing, 6B−B′=I6B-B'=I, so B′=6B−IB'=6B-I and 36B−6I−B=I36B-6I-B=I: B=I5B=\frac I5. Then A=I5A=\frac I5 too, and 10A+5B=3I310A+5B=3I_3.