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← JEE Main 2016 · 3 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 85 of 90

JEE Main 2016 · 3 Apr · Shift 1, Mathematics question 85

Let a⃗\vec a, b⃗\vec b and c⃗\vec c be three unit vectors such that a⃗×(b⃗×c⃗)=32(b⃗+c⃗)\vec a\times\left(\vec b\times\vec c\right)=\dfrac{\sqrt3}2\left(\vec b+\vec c\right). If b⃗\vec b is not parallel to c⃗\vec c, then the angle between a⃗\vec a and b⃗\vec b is :

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Answer and worked solution

Official answer: D

(a⃗⋅c⃗)b⃗−(a⃗⋅b⃗)c⃗=32b⃗+32c⃗(\vec a\cdot\vec c)\vec b-(\vec a\cdot\vec b)\vec c=\frac{\sqrt3}2\vec b+\frac{\sqrt3}2\vec c. Since b⃗\vec b and c⃗\vec c are independent, a⃗⋅b⃗=−32\vec a\cdot\vec b=-\frac{\sqrt3}2, so the angle is 5π6\frac{5\pi}6.