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← JEE Main 2016 · 3 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 84 of 90

JEE Main 2016 · 3 Apr · Shift 1, Mathematics question 84

If the line, x−32=y+2−1=z+43\dfrac{x-3}2=\dfrac{y+2}{-1}=\dfrac{z+4}3 lies in the plane, lx+my−z=9lx+my-z=9, then l2+m2l^2+m^2 is equal to :

Choose one option
Answer and worked solution

Official answer: D

The line lies in the plane, so its direction (2, −1, 3) is perpendicular to the normal: 2l−m−3=02l-m-3=0. The point (3, −2, −4) is on the plane: 3l−2m+4=93l-2m+4=9. So l=1l=1, m=−1m=-1 and l2+m2=2l^2+m^2=2.