Skip to content
dronacharya.ai
← JEE Advanced 2024 · Paper 1
PhysicsInteger+4Question 29 of 51

JEE Advanced 2024 · Paper 1, Physics question 12

Two large, identical water tanks, 1 and 2, kept on the top of a building of height HH, are filled with water up to height hh in each tank. Both the tanks contain an identical hole of small radius on their sides, close to their bottom. A pipe of the same internal radius as that of the hole is connected to tank 2, and the pipe ends at the ground level. When the water flows from the tanks 1 and 2 through the holes, the times taken to empty the tanks are t1t_1 and t2t_2, respectively. If H=(169)hH = \left(\dfrac{16}{9}\right)h, then the ratio t1/t2t_1/t_2 is _____.

Answer and worked solution

Official answer: 3

Let AA be the tank area and aa the hole area, with water height yy.

Tank 1: efflux speed 2gy\sqrt{2gy}, so A dydt=−a2gyA\,\dfrac{dy}{dt} = -a\sqrt{2gy}, giving
t1=Aa⋅2h2g.t_1 = \frac{A}{a}\cdot\frac{2\sqrt h}{\sqrt{2g}}.

Tank 2: the pipe drops a further height HH, so the exit speed is 2g(y+H)\sqrt{2g(y+H)}:
t2=Aa⋅2(h+H−H)2g.t_2 = \frac{A}{a}\cdot\frac{2\left(\sqrt{h+H} - \sqrt H\right)}{\sqrt{2g}}.

With H=169hH = \frac{16}{9}h: h+H−H=53h−43h=h3\sqrt{h+H} - \sqrt H = \frac{5}{3}\sqrt h - \frac{4}{3}\sqrt h = \frac{\sqrt h}{3}.

t1t2=3.\frac{t_1}{t_2} = 3.