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← JEE Advanced 2024 · Paper 1
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JEE Advanced 2024 · Paper 1, Physics question 11

A source (S) of sound has frequency 240 Hz240\,\mathrm{Hz}. When the observer (O) and the source move towards each other at a speed vv with respect to the ground (as shown in Case 1 in the figure), the observer measures the frequency of the sound to be 288 Hz288\,\mathrm{Hz}. However, when the observer and the source move away from each other at the same speed vv with respect to the ground (as shown in Case 2 in the figure), the observer measures the frequency of sound to be n Hzn\,\mathrm{Hz}. The value of nn is _____.

Two cases on a straight line, source S on the left and observer O on the right, joined by a dashed line. Case 1: S moves to the right (towards O) with speed v and O moves to the left (towards S) with speed v. Case 2: S moves to the left (away from O) with speed v and O moves to the right (away from S) with speed v.
Answer and worked solution

Official answer: 200

Let the speed of sound be cc.

Approaching: 288=240 c+vc−v  ⟹  c+vc−v=1.2288 = 240\,\dfrac{c+v}{c-v} \implies \dfrac{c+v}{c-v} = 1.2.

Receding: n=240 c−vc+v=2401.2=200n = 240\,\dfrac{c-v}{c+v} = \dfrac{240}{1.2} = 200.