(I) Q=10−3×2250=2.25 kJ and W=105×(10−3−10−6)≈0.1 kJ, so
ΔU≈2.15 kJ≈2 kJ → P.
(II) Isobaric expansion to 3V raises T from 500 K to 1500 K:
ΔU=nCvΔT=0.2×25×8×1000=4 kJ → R.
(III) Adiabatic compression to 8V with γ=35 gives P2=2×85/3=64 kPa:
ΔU=23(P2V2−P1V1)=23(2464−32)=3 kJ → T.
(IV) With vibration, Cv=27R and Cp=29R. At constant pressure:
ΔU=QCpCv=9×97=7 kJ → Q.