JEE Advanced 2022 · Paper 1 · Chemistry Q16

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ChemistryList match+3 / -1Question 52 of 54

LIST-I contains compounds and LIST-II contains reactions

Match each compound in LIST-I with its formation reaction(s) in LIST-II, and choose the correct option

LIST-I

I
$\ce{H2O2}$
II
$\ce{Mg(OH)2}$
III
$\ce{BaCl2}$
IV
$\ce{CaCO3}$

LIST-II

P
$\ce{Mg(HCO3)2 + Ca(OH)2 ->}$
Q
$\ce{BaO2 + H2SO4 ->}$
R
$\ce{Ca(OH)2 + MgCl2 ->}$
S
$\ce{BaO2 + HCl ->}$
T
$\ce{Ca(HCO3)2 + Ca(OH)2 ->}$

I → Q; II → P; III → S; IV → R

I → T; II → P; III → Q; IV → R

I → T; II → R; III → Q; IV → P

I → Q; II → R; III → S; IV → P

Answer and worked solution

Official answer: D

(I) $\ce{H2O2}$ is made from barium peroxide:
$\ce{BaO2 + H2SO4 -> BaSO4 + H2O2}\ \to\ \textbf{Q}.$

(II) $\ce{Mg(OH)2}$ is precipitated by lime:
$\ce{Ca(OH)2 + MgCl2 -> Mg(OH)2 + CaCl2}\ \to\ \textbf{R}.$
It also forms in P.

(III) $\ce{BaCl2}$ :
$\ce{BaO2 + 2HCl -> BaCl2 + H2O2}\ \to\ \textbf{S}.$

(IV) $\ce{CaCO3}$ forms when lime softens temporary hardness:
$\ce{Mg(HCO3)2 + 2Ca(OH)2 -> Mg(OH)2 + 2CaCO3 + 2H2O}\ \to\ \textbf{P}.$
It also forms in T.

Only option (D), I→Q, II→R, III→S, IV→P, has every pairing correct.

Topics:Important compounds of s-block Water and hydrogen peroxide

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JEE Advanced 2022 · Paper 1, Chemistry question 16