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ChemistryList match+3 / -1Question 53 of 54

JEE Advanced 2022 · Paper 1, Chemistry question 17

LIST-I contains metal species and LIST-II contains their properties.

[Given: Atomic number of Cr = 24, Ru = 44, Fe = 26]

Match each metal species in LIST-I with their properties in LIST-II, and choose the correct option

LIST-I

  • I
    [Cr(CN)X6]X4−\ce{[Cr(CN)6]^4-}
  • II
    [RuClX6]X2−\ce{[RuCl6]^2-}
  • III
    [Cr(HX2O)X6]X2+\ce{[Cr(H2O)6]^2+}
  • IV
    [Fe(HX2O)X6]X2+\ce{[Fe(H2O)6]^2+}

LIST-II

  • P
    t2gt_{2g} orbitals contain 4 electrons
  • Q
    μ\mu(spin-only) = 4.9 BM
  • R
    low spin complex ion
  • S
    metal ion in 4+ oxidation state
  • T
    d4d^4 species
Choose one option
Answer and worked solution

Official answer: A

Species Metal ion Field Configuration Properties
(I) [Cr(CN)X6]X4−\ce{[Cr(CN)6]^4-} Cr(II), d4d^4 strong t2g4t_{2g}^4, low spin R, T (also P)
(II) [RuClX6]X2−\ce{[RuCl6]^2-} Ru(IV), d4d^4 4d metal, low spin t2g4t_{2g}^4 P, S (also R, T)
(III) [Cr(HX2O)X6]X2+\ce{[Cr(H2O)6]^2+} Cr(II), d4d^4 high spin t2g3eg1t_{2g}^3e_g^1, 4 unpaired Q (4.9 BM), T
(IV) [Fe(HX2O)X6]X2+\ce{[Fe(H2O)6]^2+} Fe(II), d6d^6 high spin t2g4eg2t_{2g}^4e_g^2, 4 unpaired P, Q

Only option (A) lists properties that are all correct.