JEE Advanced 2014 · Paper 2 · Chemistry Q39

← JEE Advanced 2014 · Paper 2

ChemistryList match+3 / -1Question 39 of 60

Match each coordination compound in List-I with an appropriate pair of characteristics from List-II and select the correct answer using the code given below the lists.

{en = $\ce{H2NCH2CH2NH2}$ ; atomic numbers: Ti = 22; Cr = 24; Co = 27; Pt = 78}

List-I

P
$\ce{[Cr(NH3)4Cl2]Cl}$
Q
$\ce{[Ti(H2O)5Cl](NO3)2}$
R
$\ce{[Pt(en)(NH3)Cl]NO3}$
S
$\ce{[Co(NH3)4(NO3)2]NO3}$

List-II

1
Paramagnetic and exhibits ionisation isomerism
2
Diamagnetic and exhibits cis-trans isomerism
3
Paramagnetic and exhibits cis-trans isomerism
4
Diamagnetic and exhibits ionisation isomerism

P → 4; Q → 2; R → 3; S → 1

P → 3; Q → 1; R → 4; S → 2

P → 2; Q → 1; R → 3; S → 4

P → 1; Q → 3; R → 4; S → 2

Answer and worked solution

Official answer: B

P $\ce{[Cr(NH3)4Cl2]Cl}$ : Cr(III), $d^3$ , three unpaired electrons, paramagnetic. $\ce{MA4B2}$ octahedral: cis and trans. → 3.
Q $\ce{[Ti(H2O)5Cl](NO3)2}$ : Ti(III), $d^1$ , paramagnetic. Exchanging Cl⁻ and $\ce{NO3-}$ between the sphere and the counter-ion gives an ionisation isomer. → 1.
R $\ce{[Pt(en)(NH3)Cl]NO3}$ : Pt(II), $d^8$ , square planar, diamagnetic. With a symmetric chelate, no cis-trans isomers exist, but Cl⁻/ $\ce{NO3-}$ exchange gives ionisation isomers. → 4.
S $\ce{[Co(NH3)4(NO3)2]NO3}$ : Co(III), $d^6$ low spin, diamagnetic. $\ce{MA4B2}$ : cis and trans. → 2.

(B) P → 3, Q → 1, R → 4, S → 2

Topics:Isomerism in complexes Magnetic properties and colour

← Previous question Next question →

JEE Advanced 2014 · Paper 2, Chemistry question 39