JEE Advanced 2014 · Paper 2 · Chemistry Q40

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ChemistryList match+3 / -1Question 40 of 60

Match the orbital overlap figures shown in List-I with the description given in List-II and select the correct answer using the code given below the lists.

Two four-lobed d orbitals side by side whose adjacent lobes (same shading) overlap end-on along the internuclear axis.

A p orbital (shaded lobe up, open lobe down) beside a d orbital whose nearer lobes overlap sideways with matching phase.

A p orbital (open lobe up, shaded lobe down) beside a d orbital so that the sideways-overlapping lobes have opposite phase.

A d_z² orbital (lobes along the axis with a ring) pointing end-on at a four-lobed d orbital, with lobes of opposite phase meeting.

List-I

List-II

1
$p$ - $d$ π antibonding
2
$d$ - $d$ σ bonding
3
$p$ - $d$ π bonding
4
$d$ - $d$ σ antibonding

P → 2; Q → 1; R → 3; S → 4

P → 4; Q → 3; R → 1; S → 2

P → 2; Q → 3; R → 1; S → 4

P → 4; Q → 1; R → 3; S → 2

Answer and worked solution

Official answer: C

P: two d orbitals meeting lobe to lobe along the axis with the same phase: $d$ - $d$ σ bonding → 2.
Q: a p orbital overlapping side-on with a d lobe of matching phase: $p$ - $d$ π bonding → 3.
R: the same side-on overlap, but with opposite phases: $p$ - $d$ π antibonding → 1.
S: a $d_{z^2}$ lobe pointing end-on at a d lobe of opposite phase: $d$ - $d$ σ antibonding → 4.

(C) P → 2, Q → 3, R → 1, S → 4

Topics:Molecular orbital theory Orbitals and their shapes

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JEE Advanced 2014 · Paper 2, Chemistry question 40