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← JEE Advanced 2013 · Paper 1
ChemistryMultiple correct+4 / -1Question 35 of 60

JEE Advanced 2013 · Paper 1, Chemistry question 35

The initial rate of hydrolysis of methyl acetate (1 M) by a weak acid (HA, 1 M) is 1/100th^\text{th} of that of a strong acid (HX, 1 M), at 25 °C. The KaK_a of HA is

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Answer and worked solution

Official answer: A

Rate ∝ [H⁺]. The weak acid gives 1100\frac1{100} of the strong acid's [HX+]=1[\ce{H+}]=1 M, i.e. 0.01 M.

Ka. [HX+]=KaC[\ce{H+}]=\sqrt{K_aC} gives 10−4=Ka×110^{-4}=K_a\times1, so Ka=1×10−4K_a=1\times10^{-4}.

(A)