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← IIT-JEE 2012 · Paper 1
ChemistryInteger+4Question 38 of 60

IIT-JEE 2012 · Paper 1, Chemistry question 38

When the following aldohexose exists in its D-configuration, the total number of stereoisomers in its pyranose form is
OHC−CHX2−CH(OH)−CH(OH)−CH(OH)−CHX2OH\ce{OHC-CH2-CH(OH)-CH(OH)-CH(OH)-CH2OH}

Open-chain 2-deoxyaldohexose drawn vertically: CHO, CH₂, CHOH, CHOH, CHOH, CH₂OH.
Answer and worked solution

Official answer: 8

The sugar is a 2-deoxyaldohexose: C2 is CHX2\ce{CH2}, and C3, C4, C5 are stereocentres.

D-configuration fixes C5. C3 and C4 can each be either way: 22=42^2=4 open-chain D-isomers.

Pyranose form. Ring closure creates a new stereocentre at C1 (α or β anomer), doubling the count: 4×2=84\times2=8.

Answer: 8