IIT-JEE 2012 · Paper 1 · Chemistry Q39

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ChemistryInteger+4Question 39 of 60

29.2% (w/w) HCl stock solution has a density of 1.25 g mL⁻¹. The molecular weight of HCl is 36.5 g mol⁻¹. The volume (mL) of stock solution required to prepare a 200 mL solution of 0.4 M HCl is

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Answer and worked solution

Official answer: 8

Molarity of the stock. One litre has mass 1250 g, of which $0.292\times1250=365$ g is HCl:
$\frac{365}{36.5}=10\ \mathrm{mol\,L^{-1}}.$

Dilution. $10\times V=0.4\times200$ , so $V=8$ mL.

Answer: 8

Topics:Concentration terms

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IIT-JEE 2012 · Paper 1, Chemistry question 39