The number of hexagonal faces that are present in a truncated octahedron is
← IIT-JEE 2011 · Paper 2
ChemistryInteger+4Question 16 of 60
IIT-JEE 2011 · Paper 2, Chemistry question 16
Answer and worked solution
Official answer: 8
Truncated octahedron. Cutting each of the 6 vertices of an octahedron gives 6 square faces. Each of the 8 triangular faces becomes a hexagon.
Answer: 8 (8 hexagons + 6 squares, 14 faces)